Home
Class 10
MATHS
sec0^@ = ……….....

`sec0^@` = ………..

A

`-1`

B

1

C

0

D

7

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • TANGENTS AND SECANTS TO A CIRCLE

    VGS PUBLICATION-BRILLIANT|Exercise EXERCISE|201 Videos
  • TRIGONOMETRY (MULTIPLE CHOICE QUESTION)

    VGS PUBLICATION-BRILLIANT|Exercise TRIGONOMETRY (MULTIPLE CHOICE QUESTION)|25 Videos

Similar Questions

Explore conceptually related problems

Discuss with your friends about the following conditions: sec 0^(@) =1 Why?

The general solution of tanysec^(2) x dx + tan x sec^(2) y dy = 0 is

Find the general solutions of the following differential equations. (i) tan y.sec^(2) xdx + tan x.sec^(2)ydy = 0 (ii) tan ydx + tan xdy = 0

The equation of curve passing through ( ) satisfying the differential equation e^(x) tan y dx + (1 + e^(x)) sec^(2) y dy = 0 is given by

(1+ sec 20^(0))(1+sec40^(0))(1+ sec80^(0))=

The rate constants of a reaction at 500 k and 700 k are 0.02"sec"^(-1) and 0.07 "sec"^(-1) respectively. Calculate the value of E_(a)

If 6 sec^(2)theta - 5 sec theta + 1 = 0 then theta =

The rate constant of zero order reaction is 2xx10^(-2) mole L /sec. If the concentration of the reactant after 25 sec is 0.5 M, the initial concentration is

The rate constant for a zero order reaction is 2xx10^(2) mol L^(-1) "sec"^(-1) .If the concentration of the reactant after 25 sec is 0.5 M., the initial concentration must have been