If the velocity v of particle moving along a straight line decreases linearly with its displacement s from `20 ms^(-1)` to a value approaching zero at s = 30 m, then acceleration of the particle at v=10m is

If the velocity v of particle moving along a straight line decreases linearly with its displacement s from 20 ms^(-1) to a value approaching zero at s = 30 m, then acceleration of the particle at v=10ms^(-1) is

If the velocity v of a particle moving along a straight line decreases linearly with its displacement from 20 m//s to a value approaching zero at s = 30 m, determine the acceleration of the particle when s = 15 m.

If the velocity v of a particle moving along a straight line decreases linearly with its position coordinates s from 50m/s to a value approaching zero at = 100 m, the time it takes to reach the 100 m position will be:

The velocity of a particle moving in a straight line is decreasing at the rate of 3 m//s per metre of displacement at an instant when the velocity is 10 m//s. Determine the acceleration of the particle at this instant.

If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

A particle is moving in a straight line and its velocity varies with its displacement as v=sqrt(4+4s) m/s. Assume s=0 at t=0. find the displacement of the particle in metres at t=1s.

Velocity of a particle moving in a straight line varies with its displacement as v=(sqrt(4 +4s))m//s. Displacement of particle at time t =0 is s = 0 . Find displacement of particle at time t=2 s .

In a linear S.H.M., the acceleration of the particle is zero, when its velocity is

A particle is moving along a straight line whose velocity - displacement graph is shown in figure. What is the acceleration when displacement is 3 m?

A particle moving in a straight in a straight line has velocity and displacement equation as v = 4 sqrt(1 + s) , where v is in m/s and s is in m. The initial velocity of the particle is: