In a triangle ABC, coordinate of A are (1,2) and the equations of the medians through B and C are respectively, `x+y=5&x=4`. Then area of `DeltaABC` (in sq. units) is:

in a triangle ABC, if A is (1,2) and the equations of the medians through B and c are x+y=5 and x=4 respectively then B must be:

In a triangle ABC, co-ordinates of A are (1,2) and the equations to the medians through B and C are x+y=5 and x=4 respectively.Then the co-ordinates of B and C will be

The vertex A of triangle ABC is at origin.The equation of median through B and C are 15x-4y=240 and 15x-52y+240=0 respectively.Then

In a triangle ABC.if A(1,2) and the internal angle bisetors through B and C are y=x and y=-2x, then the in radius r of Delta ABC is :

Let ABC be a triangle such that the coordinates of A are (–3, 1). Equation of the median through B is 2x + y – 3 = 0 and equation of the angular bisector of C is 7x – 4y – 1 = 0. Then match the entries of column-I with their corresponding correct entries of column-II

If the area of the triangle is 4sq units, then x is

The slope of a median, drawn from the vertex A of the triangle ABC is -2. The co-ordinates of vertices B and C are respectively (-1, 3) and (3, 5). If the area of the triangle be 5 square units, then possible distance of vertex A from the origin is/are.

If G is the centriod of Delta ABC and if area of Delta AGB is 5 sq units.Then area of Delta ABC is P sq units then value of P is

Let ABC be a triangle such that the coordinates of the vertex A are (3,1). Equation of the median through B is 2x+y-3=0 and equation of the angular bisector of C is 7x-4y-1=0. Find the slope of line BC.