An infinite line of charge `lamda` per unit length is placed along the y-axis. The work done in moving a charge q from `A(a,0)` to `B (2a,0)` is

For an infinite line of charge having linear charge density lambda lying along x-axis the work done in moving a charge q form C to A along CA is

The diagram shows three infinitely long uniform line charges placed on the X, Y and Z axis . The word done in moving a unit positive charge from (1,1,1) to (0 , 1,1,) is equal to .

The work done to move a charge along an equipotential from A to B

There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring Q=4sqrt(2lambda)R . An electron of mass m is released from rest on the axis of the ring at a distance x=sqrt(3) R from the centre. The distance from centre of ring on the axis where the net force on the electron is zero.

There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring Q=4sqrt(2lambda)R . An electron of mass m is released from rest on the axis of the ring at a distance x=sqrt(3) R from the centre. Potential difference between points A(x=sqrt(3)R) and B(x=R)i.e.(V_(A)-V_(B)) is

There is a uniformly charged ring having radius R. An infinite line charge (charge per unit length lambda) is placed along a diameter of the ring (in gravity free space). Total charge on the ring Q=4sqrt(2lambda)R . An electron of mass m is released from rest on the axis of the ring at a distance x=sqrt(3) R from the centre. Magnitude of initial acceleration of the electron.

A charge +q is placed at the origin O of X- Y axes as shown in the figure . The work done in taking a charge Q from A to B along the straight line AB is

As per this diagram a point charge +q is placed at the origin O . Work done in taking another point charge -Q from the point A(0, a) to another point B(a, 0) along the staight path AB is: