` lim_(x->0) xlog x`

lim_(x->0)|sinx|/x

If lim_(xrarroo) xlog_(e)(|(alpha//x,1,gamma),(0,1//x,beta),(1,0,1//x)|)=-5. then

Let a=lim_(x rarr0)x cot x and b=lim_(x rarr0)x log x then

if l=lim_(x->0) (x(1+acosx) - bsinx)/x^3 = lim_(x->0) (1+acosx)/x^2-lim_(x->0) (b sinx)/x^3 where l in R , then

if l=lim_(x->0) (x(1+acosx) - bsinx)/x^3 = lim_(x->0) (1+acosx)/x^2-lim_(x->0) (b sinx)/x^3 where l in R , then

lim_(x->0) (ln(2+x)+ln0.5)/x

lim_(x to 0) (cos x)/(pi-x)

Evaluate : lim_( x -> 0 ) Sin( x^(@ ) )/x