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The square of angular velocity omega of ...

The square of angular velocity `omega` of a certain wheel increases linearly with the angular displacement `theta` during 100 revolutions of the wheel's motion as shown in the figure. The time `t` required for given 100 revolutions is `(10 m pi)/(n)`. Find `(m+n)`.
'(##CEN_KSR_PHY_JEE_C07_028_Q17##)'

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