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A gaseous mixture enclosed in a vessel of volume `V` consists of one gram mole of gas `A` with `gamma=(C_(P))/(C_(F))=(5)/(3)` and another gas `B` with `gamma=(7)/(5)` at a certain temperature `T`. The gram molecular weights of the gases `A` and `B` are 4 and 132 , respectively. The gases `A` and `B` do not react with cach other and are assumed to be ideal. The gaseous mixture follows the equation `P Y^(19 / 13)=` Constant, in adiabatic process. Find the inumber of gram moles of the gas `B` in the gaseous mixture.

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A gaseous mixture enclosed in a vessel of volume V consists of one gram mole of gas A with gamma = (C_(P))/(C_(V)) = (5)/(3) an another gas B with gamma = (7)/(5) at a certain temperature T . The gram molecular weights of the gases A and B are 4 and 32 respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13) = constant , in adiabatic process. Find the number of gram moles of the gas B in the gaseous mixture.

A gaseous mixture enclosed in a vessel of volume V consists of one mole of a gas A with gamma=(C_p//C_v)=5//3 and another gas B with gamma=7//5 at a certain temperature T. The relative molar masses of the gasses A and B are 4 and 32, respectively. The gases A and B do not react with each other and are assumed to be ideal. The gaseous mixture follows the equation PV^(19//13)=constant , in adiabatic processes. (a) Find the number of moles of the gas B in the gaseous mixture. (b) Compute the speed of sound in the gaseous mixture at T=300K . (c) If T is raised by 1K from 300K, find the % change in the speed of sound in the gaseous mixture. (d) The mixtrue is compressed adiabatically to 1//5 of its initial volume V. Find the change in its adaibatic compressibility in terms of the given quantities.

A gaseous mixture enclosed in a vessel consists of one gram mole of a gas A with gamma=(5/3) and some amount of gas B with gamma=7/5 at a temperature T. The gases A and B do not react with each other and are assumed to be ideal. Find the number of gram moles of the gas B if gamma for the gaseous mixture is (19/13) .

The molecular weights of two ideal gases A and B are respectively 100 and 200. One gram of A occupies V litre of volume at STP. What is the volume (in litre) occupied by one gram of B at STP ?

One mole of an ideal monoatomic gas is mixed with one mole of an equimolar mixture of monoatomic and diatomic ideal gases. Find the value of lambda= (C_P /C_v) for the final mixture

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