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One mole of a diatomic gas undergoes 'a ...

One mole of a diatomic gas undergoes 'a process `P=(P_(0))/(1+((V)/(V_(0)))^(s),)` where `P_(0), V_(0)` are constants. The translational kinetic energy of the gas when `V=V_(0)` is given by `(alpha P_(0) V_(0))/(beta)`, Find `(alpha+beta)`.

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