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A simple pendulum in oscillation has a m...

A simple pendulum in oscillation has a maximum angular displacement of `(pi)/(72) rad`, and a time period of `2 s`, then angular speed at the instant when it's angular displacement is `(3 pi)/(360)` is `(k pi^2)/(360)`. Find k.

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To solve the problem step by step, we will follow the outlined approach: ### Step 1: Identify Given Values - Maximum angular displacement, \( \theta_0 = \frac{\pi}{72} \) rad - Time period, \( T = 2 \) s - Angular displacement at the instant, \( \theta = \frac{3\pi}{360} = \frac{\pi}{120} \) rad ### Step 2: Calculate Angular Frequency The angular frequency \( \omega \) can be calculated using the formula: \[ \omega = \frac{2\pi}{T} \] Substituting the value of \( T \): \[ \omega = \frac{2\pi}{2} = \pi \text{ rad/s} \] ### Step 3: Use the Equation of Motion for Angular Displacement The equation for angular displacement in simple harmonic motion is: \[ \theta = \theta_0 \sin(\omega t) \] We need to find \( \sin(\omega t) \) when \( \theta = \frac{\pi}{120} \): \[ \frac{\pi}{120} = \frac{\pi}{72} \sin(\omega t) \] Dividing both sides by \( \frac{\pi}{72} \): \[ \sin(\omega t) = \frac{\frac{\pi}{120}}{\frac{\pi}{72}} = \frac{72}{120} = \frac{3}{5} \] ### Step 4: Find \( \cos(\omega t) \) Using the Pythagorean identity: \[ \sin^2(\omega t) + \cos^2(\omega t) = 1 \] Substituting \( \sin(\omega t) = \frac{3}{5} \): \[ \left(\frac{3}{5}\right)^2 + \cos^2(\omega t) = 1 \] \[ \frac{9}{25} + \cos^2(\omega t) = 1 \] \[ \cos^2(\omega t) = 1 - \frac{9}{25} = \frac{16}{25} \] Thus, \[ \cos(\omega t) = \frac{4}{5} \] ### Step 5: Calculate Angular Speed The angular speed \( \omega \) at any time \( t \) is given by: \[ \omega = \frac{d\theta}{dt} = \theta_0 \cdot \omega \cdot \cos(\omega t) \] Substituting the known values: \[ \omega = \frac{\pi}{72} \cdot \pi \cdot \frac{4}{5} \] \[ \omega = \frac{4\pi^2}{360} \] ### Step 6: Compare with Given Expression We are given that the angular speed can be expressed as: \[ \omega = \frac{k \pi^2}{360} \] From our calculation, we have: \[ \frac{4\pi^2}{360} = \frac{k \pi^2}{360} \] This implies: \[ k = 4 \] ### Final Answer Thus, the value of \( k \) is: \[ \boxed{4} \]
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