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A positively charged oil droplet remains...

A positively charged oil droplet remains in the electric field between two horizontal plates, separated by a distance `1cm`. If the charge on the drop is `3: 3 xx 10^{-3} C` and the mass of the droplet is `10^14 kg`, then what is the potential difference (in volt) between the plates? (Take `g= 9.9ms^(2)` )

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Knowledge Check

  • A positively charged oil droplet remins stationary in the electric field between two horizontal plates separated by a distance of 1 cm . The charge on the drop is 10^(-15) C and mass of the droplet is 10^(-11) g , the potential difference between the plates and if the polarity is reversed , the instantaneous of the droplet are

    A
    `1V , 9.8 m//sec^(2)`
    B
    `1 V , 0 m//sec^(2)`
    C
    `1V ,19.6 m//sec^(2)`
    D
    `2V ,19.6 m//sec^(2)`

  • A condenser having circular plates having radius 2cm and separated by a distance of 3 mm . It is charged with a current of 0.1 A . The rate at which the potential difference between the plates change is

    A
    `9xx10^(10)V//S`
    B
    `1.8xx10^(10)V//S`
    C
    `2.7xx10^(6)V//S`
    D
    `2.7xx10^(10)V//S`

  • In Millikan's experiment, an oil drop having charge q gets stationary on applying a potential difference V in between two plates separated by a distance 'd'. The weight of the drop is

    A
    `qVd`
    B
    `q(d)/(V)`
    C
    `(q)/(Vd)`
    D
    `q(V)/(d)`
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