The magnetic moment of a magnet of mass 75 g is `9 xx 10^(-3) A m^(2)`. If the density of the material of magnet is `7.5 xx 10^(3) kg / m^(3)`, then intensity of magnetization (in (A/ `m^2` ) will be

Answer

To find the intensity of magnetization (I) of the magnet, we can use the following formula:

\[ I = \frac{M}{V} \]

where:
- \( M \) is the magnetic moment,
- \( V \) is the volume of the magnet.

### Step 1: Convert the mass from grams to kilograms.
Given mass = 75 g.

To convert grams to kilograms:
\[ \text{Mass in kg} = \frac{75 \text{ g}}{1000} = 0.075 \text{ kg} \]

### Step 2: Calculate the volume of the magnet using the density formula.
The density (\( \rho \)) is given by:
\[ \rho = \frac{m}{V} \]
Rearranging this formula to find volume (\( V \)):
\[ V = \frac{m}{\rho} \]

Substituting the values:
\[ V = \frac{0.075 \text{ kg}}{7.5 \times 10^3 \text{ kg/m}^3} \]

Calculating the volume:
\[ V = \frac{0.075}{7500} = 1 \times 10^{-5} \text{ m}^3 \]

### Step 3: Calculate the intensity of magnetization.
Using the formula for intensity of magnetization:
\[ I = \frac{M}{V} \]

Substituting the values:
\[ I = \frac{9 \times 10^{-3} \text{ A m}^2}{1 \times 10^{-5} \text{ m}^3} \]

Calculating \( I \):
\[ I = 9 \times 10^{2} \text{ A/m}^2 = 900 \text{ A/m}^2 \]

### Final Answer:
The intensity of magnetization is \( 900 \text{ A/m}^2 \).

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