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In a single slit diftion, slit width is ...

In a single slit diftion, slit width is `0.6mm` and distance of first minima from central position is `1 mm`. If screen distance is `1.2m`, then wavelength of light (in nm) is

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A single slit is of width 0.5mm . Distance of screen from slit is 1 m . Second maxima in diffiraction pattern is at distance 2 mm from centre. What is wavelength of light (in nm )?

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Knowledge Check

  • In Young's experiment, the distance between two slit is 0.8 mm and distance of screen from slit is 1.2 m. If the fringe width is 0.79 mm, then the wave length of light will be

    A
    4267 A.U
    B
    3267 A.U
    C
    5267 A.U.
    D
    5537 A.U
  • Light of wavelength lambda is incident on a slit. First minima of the diffraction pattern is found to lie at a distance of 6 mm from the central maximum on a screen placed at a distance of 2 m from the slit. If slit width is 0.2 mm, then wavelength of the light used will be :

    A
    `4000 Å`
    B
    `6000 Å`
    C
    `7000 Å`
    D
    `7400 Å`
  • In a single slit diffraction of light of wavelength lambda by a slit of width e, the size of the central maximum on a screen at a distance b is

    A
    (a) `2blambda+e`
    B
    (b) `(2blambda)/(e)`
    C
    (c) `(2blambda)/(e)=e`
    D
    (d) `(2blambda)/(e)-e`
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    In a single slit diffraction pattern, the distance between first minima on the right and first minima on the left of central maximum is 4mm . The screeon on which the pattern is displaced is 2m from the slit and wavelength of light used is 6000Å . Calculate width of the slit and width of the central maximum.

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