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Lights of two different frequencies whose photons have energies `1 eV` and `2.5eV` illuminate a metallic surface whose work function is `0.5eV` successively. The ratio of maximum speed of emitted electrons in the first case to that in the second case will be

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0.5
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  • Light of two different frequencies whose photons have energies 1eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum kinetic energy of emitted electrons will be:

    A
    `1:4`
    B
    `1:2`
    C
    `1:1`
    D
    `1:5`

  • Lights of two different frequencies whose photons have energies 1 and 2.5 eV, respectively, successively illuminate a metal whose work function is 0.5 eV. The ratio of the maximum speeds of the emitted electrons

    A
    `1:5`
    B
    `1:4`
    C
    `1:2`
    D
    `1:1`

  • Lights of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate successively a metal surface whose work function is 0.6 eV. The ratio of the maximum speeds of the emitted electrons will have

    A
    `1:2`
    B
    `1:3`
    C
    `1:4`
    D
    `1:5`

    • Similar Questions

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    Two radiation of photons energy 3eV and 4.5 eV successively illuminate a photosensitive metallic surface of work function 2.5 eV the ratio of the maximum speeds of the emitted electrons is :-

    Photons of energy 1.5 eV and 2.5 eV are incident on a metal surface of work function 0.5 eV. What is the ratio of the maximum kinetic energy of the photoelectrons ?

    Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

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