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A graph of sqrt(v) ( where v is the freq...

A graph of `sqrt(v)` ( where `v` is the frequency of `K_(alpha)` line of the characteristic X-ray spectrum) is plotted against the atomic number `Z` of the elements emitting the characteristic X-ray .The intercept of the graph on the `z` -axis is 1 and the slope of the graph is `0.5 xx 10^(8)` in SI units. The frequency of the `K_(alpha)` line for an element of atomic number 41 is given as `alpha times 10^(16) Hz`. Find the value of `alpha`.

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To solve the problem, we need to analyze the relationship between the frequency of the K-alpha line of characteristic X-ray spectrum and the atomic number \( Z \) of the elements. The relationship is given by the linear equation derived from the graph of \( \sqrt{v} \) versus \( Z \). ### Step-by-Step Solution: 1. **Understanding the Graph**: The graph of \( \sqrt{v} \) (where \( v \) is the frequency of the K-alpha line) against the atomic number \( Z \) can be expressed in the linear form: \[ \sqrt{v} = mZ + c \] where \( m \) is the slope and \( c \) is the intercept. 2. **Given Values**: - The intercept \( c = 1 \) - The slope \( m = 0.5 \times 10^8 \) 3. **Equation of the Line**: Substituting the values into the linear equation: \[ \sqrt{v} = (0.5 \times 10^8)Z + 1 \] 4. **Finding \( v \) for \( Z = 41 \)**: We need to find the frequency \( v \) when \( Z = 41 \): \[ \sqrt{v} = (0.5 \times 10^8)(41) + 1 \] 5. **Calculating \( \sqrt{v} \)**: Calculate \( (0.5 \times 10^8)(41) \): \[ (0.5 \times 10^8)(41) = 20.5 \times 10^8 \] Now add 1: \[ \sqrt{v} = 20.5 \times 10^8 + 1 \approx 20.5 \times 10^8 \quad (\text{since } 1 \text{ is negligible in comparison}) \] 6. **Squaring to Find \( v \)**: Now square both sides to find \( v \): \[ v = (20.5 \times 10^8)^2 \] \[ v = 420.25 \times 10^{16} \quad (\text{since } (10^8)^2 = 10^{16}) \] 7. **Expressing \( v \) in terms of \( \alpha \)**: We know that \( v = \alpha \times 10^{16} \). Therefore: \[ \alpha \times 10^{16} = 420.25 \times 10^{16} \] 8. **Finding \( \alpha \)**: From the above equation, we can equate: \[ \alpha = 420.25 \] ### Final Answer: The value of \( \alpha \) is \( 420.25 \).
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