An object of mass m is projected with a momentum p at such an angle that its maximum height is `1//4` th of its horizontal range. Its minimum kinetic energy in its path will be

A particle of mass m is projected from the ground with initial linear momentum p (magnitude) such that to have maximum possible range, its minimum kinetic energy will be

A projectile is projected with a kinetic energy K . If it has the maximum possible horizontal range, then its kinetic energy at the highest point will be

A stone is projected vertically up to reach maximum height h. The ratio of its potential energy to its kinetic energy at a height 4/5h , will be

A body is projected vertically up with a valocity u. its velocity at ghalf of its maximum height and at 3//4th of its maximum height are.

A body is projected with velocity u so that its horizontal range is twice the maximum height.The range is

A particle of mass m has momentum p. Its kinetic energy will be

A particle is projected from the ground with a kinetic energy E at an angle of 60° with the horizontal. Its kinetic energy at the highest point of its motion will be

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is .

A particle of mass m is projected with a velocity mu at an angle of theta with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :