Two stones of masses `m` and `2m` are whirled in horizontal circles, the heavier one in a radius `(r)/(2)` and the lighter one in radius `r` . The tangential speed of light stone is `n` times that of the value heavier stone when they experience same centripetal forces. The value of `n` is:

Two stone of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius r//2 and the lighter one in radius r . The tangential speed of lighter stone is n times that of the value of heavier stone when thy experience same centripetal forces. the value of n is

Two stones A and B are whirled in different horizontal circular paths. Stone A is 3 times heavier than B and moving in radius twice as that of radius of B and with speed one third as that of the speed of B. The ratio of centripetal forces acting on A and B will be

A stone of mass 1 kg is rotated in a horizontal circle of radius 0.5 m. If it makes (100)/(pi) r.p.s. then its angular momentum is

A stone of mass 4kg is whirled in a horizontal circle of radius 1m and makes 2 rev/sec. The moment of inertia of the stone about the axis of rotation is

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -

A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by T = Ar^2 where A is a constant, r is the instantaneous radius fo the circle and n=....