A stone weighing 1 kg is ties to a string of 1m length and whirled over the horizontal top of a rough plane with a speed of `2 ms^(-1)`. Calculate the tension of the string if the coefficient of friction between the table and the stone is 0.3

A stone is tied to the end of a string of length 1 and whirled in a horizental circle. When the string breaks then stone

A stone of mass 250 gram , attached at the end of a string of length 1.25 m is whirled in a horizontal circle at a speed of 5 m/s . What is the tension in the string ?

Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity 2 rad s^(-1) . The tension of the string is (in newton)

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniforn speed of 2m//s .Then tension in the string is

A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of 3 ms^(-1) . The tension in the string will be 19 N when the stone is (g=10 ms^(-1))

A particle of mass m is tied to a string of length L and whirled into a horizontal plan. If tension in the string is T then the speed of the particle will be :

A stone of mass 0.1 kg tied to one end of a string lm long is revolved in a horizontal circle at the rate of (10)/(pi)" rev/s" . Calculate the tension in the string.

A stone of mass 4 kg is attached to a string of 10 m length and is whirled in a horizontal circle. The string can withstand a maximum tension of 160 N. Calculate the maximum velocity of revolution that can be given to the stone without breaking the string.