Let `A=[(2,0,7),(0,1,0),(1,-2,1)] and B=[(-k,14k,7k),(0,1,0),(k,-4k,-2k)]`. If `AB=I`, where I is an identity matrix of order 3, then the sum of all elements of matrix B is equal to

If A=[(1,0),(-1,7)] and l is an identity matrix of order 2, then the value of k, if A^(2)=8A+kI , is :

Let A = ((1,-1,0),(0,1,-1),(0,0,1))andB=7A^(20)-20A^(7)+2I, where I is an identity matrix of order 3 xx 3 if B = [b_(ij)] then b_(13) is equal to __________ .

A=[[0,1],[3,0]]" and let "BV=[[0],[11]]" Where "B=A^(8)+A^6+A^(4)+A^(2)+I," (Where "I" is the "2times2" identity matrix) then the product of all elements of matrix "V" is "

If A is a square matrix of order 2, |A| ne 0 and |4A| = k |A|, then the value of k is :

let P_(1)=[(1,0,0),(0,1,0),(0,0,1)],P_(2)=[(1,0,0),(0,0,1),(0,1,0)],P_(3)=[(0,1,0),(1,0,0),(0,0,1)],P_(4)=[(0,1,0),(0,0,1),(1,0,0)],P_(5)=[(0,0,1),(1,0,0),(0,1,0)],P_(6)=[(0,0,1),(0,1,0),(1,0,0)] and X=sum_(k=1)^(6) P_(k)[(2,1,3),(1,0,2),(3,2,1)]P_(k)^(T) Where P_(k)^(T) is transpose of matrix P_(k) . Then which of the following options is/are correct?

If A=[(0,3),(-7,5)] and I=[(1,0),(0,1)] , then find 'k' so that k^(2)=5A-21I .

Let matrix B be the adjoint of a square matrix A.I be the identity matrix of same order as A. If k(ne 0) is the determinant of the matrix A. then what is AB equal to ?

A=[{:(1,0,k),(2, 1,3),(k,0,1):}] is invertible for