A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz . The maximum acceleration of the particle is

For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2s . Find the acceleration and velocity of the body when the displacement is (a) 5cm, (b) 3cm, (c) 0 cm.

A particle is executing simple harmonic motion with an amplitude of 10 cm and time period of 4s. Calculate its displacement, velocity and acceleration after 1/2 seconds, starting from the mean position.

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

If a particle is executing simple harmonic motion, then acceleration of particle

A particle executes simple harmonic motion with an amplitude of 4cm At the mean position the velocity of tge particle is 10 earth distance of the particle from the mean position when its speed 5 point is

A simple harmonic motion of amplitude A has a time period T. The acceleration of the oscillator when its displacement is half the amplitude is

The equation of motion of a particle executing simple harmonic motion is a+16pi^(2)x = 0 In this equation, a is the linear acceleration in m//s^(2) of the particle at a displacement x in meter. The time period in simple harmonic motion is