Water of volume 2 litre in a container is heated with a coil of `1kW at 27^@C.` The lid of the container is open and energy dissipates at rate of `160J//s.` In how much time temperature will rise from `27^@C to 77^@C` Given specific heat of water is
`[4.2kJ//kg`]

Water of volume 4L in a closed container is heated with a coil of 2 kW. While water is heated, the container loses energy at a rate of 120 J/s. In how much time will the temperature of water rise from 27^(@)C to 77^(@)C ? (Specific heat of water is 4.2 kJ/kg and that of the container is negligible).

A kettle with 2 litre water at 27^@C is heated by operating coil heater of power 1 kW. The heat is lost to the atmosphere at constant rate 160 J//s , when its lid is open. In how much time will water heated to 77^@C with the lid open ? (specific heat of water = 4.2 kJ//^@C-kg)

A system absorbs 10 kJ of heat at constant volume and its temperature rises from 27^(@)C to 37^(@)C . The DeltaE of reaction is

2 litres water at 27^(@)C is heated by a 1kW heater in an open container. On an average heat is lost to surroundings at the rate 160 J//s . The time required for the temperature to reach 77^(@)C is

Calculate the amount of heat energy required to increase the temperature of 250 g of water from 27^(@)C to 67^(@)C (Specific heat capacity of water is 1 cal g^(-1@)C^(-1) )