Two sound sources are moving away from a stationary observer in opposite direction with velocities `V_1` and `V_2(V_1gtV_2)`. The frequency of both the sources is 900 Hz. `V_1` and `V_2` are both quite less than speed of sound, `V=300(m)/(s)`. Find the value of `(V_1-V_2)` so that beat frequency observed by observer is 9 Hz. (in m/s).

Two sound sources are moving in opposite directions with velocities v_1 and v_2(v_1gtv_2) . Both are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v_1-v_2 so that the beat frequency observed by the observer is 6 Hz? Speed of sound v=300(m)/(s) . Given that v_1 and v_2ltltltv .

Two sources of sound are moving in opposite directions with velocities V_(1) and V_(2)(V_(1) gt V_(2)) . Both are moving away from a stationary observer. The frequency of both the source is 1700Hz. What is the value of (V_(1)-V_(2)) so that the beat frequency observed by the observer is 10Hz. V_("sound")=340m//s and assume that V_(1) and V_(2) both are very much less than V_("sound") .

two sound sources are moving in oppostive directions with velocities v_(1) and v_(2) ( v_(1) gt v_(2)) . Both are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of v_(1) - v_(2) so that the beat frequency aboserved by the observer is 6 Hz. speed of sound v= 300 m/s given ,that v_(1) and v_(2) lt lt v

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