An `e^(-)` of mass `m` is released from rest under gravity.An electric field `E=(mg)/(e) is applied upwards,find the accleration of electron.?

A particle of mass m and charge q is released from rest in uniform electric field of intensity E. Calculate the kinetic energy it attains afect moving a distance x between the plates.

A charged particle of mass m and charge e is released from rest in an electric field E. If kinetic energy of particle after time t is E_k and linear momentum is p, then

A charged particle of mass m and charge e is released from rest in an electric field of constant magnitude E. The kinetic energy of the particle after time t is E_k and the linear momentum is p. We have

A charged particle of mass m and charge q is released from rest in an electric field of constant magnitude E . The kinetic energy of the particle after time t is

A ball of mass m having a charge q is released from rest in a region where a horizontal electric field E exists. (a) Find the resultant force acting on the ball. (b) Find the trajectory followed by the ball.

There exists a uniform electric field between plates A and B. An electron and proton, initially at rest are released from plates A and B respectively. If a_(e) and a_(p) stand for the acceleration of electron and proton respectively then

Electric Field||E due to rods