An ammeter is obtained by shunting a `30 Omega` galvanometer with a `30 Omega` resistance. What additional shunt should be connected across it to double the range ?

An ammetre is obtained by shunting a 30 Omega galvanometer with a 30 Omega resistance. What additional shunt should be connected across it to double the range ?

In an ammeter, 10% of the main current is passing through galvanometer, it the galvanometer is shunted with a 10 Omega resistance. What is the resistance of the galvanometer ?

The resistance of an ammeter is 13 Omega and its scale is graduated fro a current upto 100 A . After an additional shunt has been connected to this ammeter it becomes possible to measure currents upto 750 A by this meter. The value of shunt resistance is

A moving coil galvanometer of resistance 20 Omega gives a full scale deflection when a current of 1mA is passed through it. It is to be converted into an ammeter reading 20 A on full scale. But the shunt of 0.005 Omega only is available. What resistance should be connected in series with the galvanometer coil?

When a galvanometer of resistance G is shunted with a low resistance S, then the effective resistance R_(eff) of galvanometer becomes R_(eff)=(GS)/(G+S) If current is passed through such a galvanometer, then the major amount of current flows through shunt and the rest through galvanometer, i.e., the current divides itself in the inverse ratio of resistance. Read the above passage and answer the following questions: (i) Why is the resistance of shunted galvanometer lower than that of shunt? (ii) A galvanometer of resistance 30Omega is shunted by a resistance of 3Omega . What fraction of the main current passes (i) through the galvanometer and (ii) through the shunt? (iii) What are the basic values you learn from the above study?