`" Let "A" be a "3times3" matrix such that "A[[1,2,3],[0,2,3],[0,1,1]]=[[0,0,1],[1,0,0],[0,1,0]]" .Then "A^(-1)" is "`

Let a be a 3xx3 matric such that [(1,2,3),(0,2,3),(0,1,1)]=[(0,0,1),(1,0,0),(0,1,0)] , then find A^(-1) .

Let A be a 3times3 real matrix such that A([1],[0],[1])=2([1],[0],[1]),A([-1],[0],[1])=4([-1],[0],[1]),A([0],[1],[0])=2([0],[1],[0]) Then,the system (A-3I)([x],[y],[z])=([1],[2],[3]) has :

If A=|[1,0,1],[0,1,2],[0,0,4]| then |3A|

If A is a 2times2 matrix such that [[2,1],[3,2]] A [[-3,2],[5,-3]]=[[1,0],[0,1]] then the sum of the elements in A is

Evaluate : [[1,3,5]][[1,0,3],[2,0,1],[0,1,2]][[1],[4],[6]]

If A=[[-3,1,2],[0,0,1],[-3,5,0]] ,then 8|A|

8.Find the rank of the matrix [[0,1,-3,-1],[1,0,1,1],[3,1,0,2],[1,1,-2,0]]

Solve the matrix equation A[[1,2],[3,4]]=[[1,-1],[0,0],[2,3]] using concept of inverse.

Evaluate the following : [[1,-1],[0,2],[2,3]]([[1,0,2],[2,0,1]]-[[0,1,3],[1,0,2]])