A particle starts from the origin,goes along the "X" - axis to the point(20m,0) and then returns along the same line to the point (-20m,0 then the displacement of the particle during the trip in negative direction is....(in m )

A particle starts from the origin, goes along the X-axis to the pont (20m, 0) and then returns along the same line to the point (-20m,0). Find the distance and displacement of the particle during the trip.

A particle starts from the origin, goes along X-axis to the point (30m, 0) and then returns along the same line to the point (-30m,0). The displacement and distance of the particle during the trip are

A particle starts from the origin, goes along x-axis to the point (10 m, 0) and then returns along. The same line to the point (-10 m, 0). The distance and displacement of the particle during the trip are

A particle starts at the origin and moves along the x-axis in such a way that its velocity at the point (x,0) is given by the formula (dx)/(dt)=cos^(2)pi x. Then the particle never reaches the point on

A particle moves from a point (2m, 3m, 0) to (3 m, 2m, 0) under the action of force of magnitude 5N acting along the line y= x . The work done by the force on the particle during the displacement is

Three particles start from the origin at the same time, one with velocity u_1 along the x-axis, the second with velocity u_2 along the y-axis . Find the velocity of the third particles, along the x=y line so that the three particles may always lie on the same straight line.

A force vec((F)) = - K(yhat(i) + x hat(j)) (where K is a positive constant) acts on a particle moving in the X-Y plane. Starting from the origin, the particle is taken along the positive X-axis to the point (a, 0) and then parallel to the Y-axis to the point (a,a). The total done by the force vec(F) . of the particle is

A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

A force vecF=(4hati+5hatj)N acts on a particle moving in XY plane. Starting from origin, the particle first goes along x-axis to the point (5.0) m and then parallel to the Y-axis to the point (5,4 m. The total work done by the force on the particle is

A particle moves from a point (2 m, 3 m, 0) to (3 m, 2 m, 0) under the action of force of magnitude 5 N acting along the line y = x. The work done by the force on the particle during the displacement is