When `3.2g` sulphur is vaporised at `450^(@)C` and `723mmHg` pressure,the vapours occupy a volume of `780ml` what is the molecular formula of S-vapour

When 3.2g of sulphur is vapourised at 450^(@)C and 723 mm pressure , the vapours occupy a volume of 780ml. What is the molecular formula of sulphur vapours under these conditions? Calculate the vapour density also.

When 3.2 gm of sulphur is vapourized at 450^(@)C and 723 mm pressure, the vapour occupies a volume of 780 m, what is the formula for the sulphur under these conditions?

At 450^(@)C and 723 mm pressure, 3.2 g of sulphur vapours occupy a volume of 780 mL. What is the molecular formula under these conditions?

3.2 g of S is heated to occupy a volume of 780 ml at 450^(@)C and 723 mm pressure. Formula of sulphure is

When 3.2gm of sulphur is vapourised,it gives 280ml of vapour at 273^(@)C and 1520mm pressure.Molecular formula of sulphur is