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Stream at 100^(@)C is passed into 20 g o...

Stream at `100^(@)C` is passed into 20 g of water at `10^(@)C`. When water acquires a temperature of `80^(@)C`, the mass of water present will be [Take specific heat of water `=1 cal g^(-1) .^(@)C^(-1)` and latent heat of steam `=540 cal g^(-1)`]

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Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

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