A particle moves according to the equation `x= a cos pi t`. The distance covered by it in `2.5` s is

A particle moves according to equation x = A cos pi t . The distance covered by it in 3.5 s is

A particle moves according to the law x = acos (pi) / (2) The distance covered by it in the time interval between t=0 to t=3s is

A particle moves according to the law x=r cos((pit)/(2)) . The distance covered by it in the time interval between t = 0 and t = 3 s in nr. What is the value of n?

A particle moves according to the law, x=acos(pit//2). . What is the distance covered by it in time interval t=0 to t=3 second.

A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particles executes SHM according to the equation y = 2 sin 2pit , where y is displacement in m and t is time in s. The distance covered by the particle in 4 s of its motion is

A particle is osicllating according to the equation X= 7 cos (0.5 pi t) , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle moves according to the equation t = ax^(2)+bx , then the retardation of the particle when x = (b)/(a) is