The displacement of a particle in `SHM` is `x = 3sin (20 pit) +4 cos(20pit)cm`. Its amplitude of oscillation is

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then acceleration of the particle at 0.1 s is

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be

The equation for the displacement of a particle executing SHM is x = 5sin (2pit)cm Then the velocity at 3cm from the mean position is( in cm//s)

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

The displacement of a particle performing S.H.M. is, x = 3 sin (314t) + 4 cos (314t), where x and t are in CGS units. Then the amplitude of the S.H.M. is,

The displacement of a particle of mass 1 kg in S.H.M. is x = 2 sin (pit+phi) m. Then variation of its PE in joule is

The equation for the displacement of a particle executing SHM is y = 5 sin (2pit)cm . Find (i) velocity at 3cm from the mean position (ii) acceleration at 0.5s after having the mean position

The displacement equation of a particle performing S.H.M. is x = 10 sin (2pit+(pi)/(6)) m. Then the initial displacement of a particle is