Comment on `C_((s))+O_(2(g)) to CO_(2(g))+Heat` equation.

In the reaction C_((s)) + CO_(2(g)) hArr CO_(2(g)) , the equilibrium pressure is 6.75 atm. If 50% of CO_(2) reacts then the find value of K_(p) .

Comment on "N_2(g) + O_2(g) + Heat rarr 2NO(g) ' equation.

Burning of coal is reprsented as C_((s))+O_(2(g))toCO_(2(g)) . The rate of this reaction is increased by

In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(P) . If K_(P)= y^(2) then what is 'y" ?

C_((s))+O_(2(g))rarr CO_(2(g))+Q is ………………….

C _((s)) + O _(2 (g)) to CO _(2(g)) ,Delta H =-393.5kJ. This equation can not represent

Which of the following holds good to the laws of thermodynamics for the reaction ? C_2H_(4(g)) + 3O_(2(g)) to 2CO_(2(g)) + 2H_2O_((l))

At 27^@C the reaction, C_6H_(6(l)) + 15/2 O_(2(g)) to 6CO_(2(g)) + 3H_2O((l)) proceeds spontaneously because the magnitude of