a = 3, b = 2, `a^bgtb^a`(T/F).

A force F is given by F at + bt^(2) where t is time. What are dimensions of 'a' and 'b'?

Find the equation of tangent to the curve given by x = a sin^(3) t , y = b cos^(3) t at a point where t = (pi)/(2) .

If the force is given by F = at + bt^(2) with t as time. The dimensions of a and b are

If A={1, 2, 3}, B={a, b, c, d}, f={(1, a), (2, b), (3, d)} , then f is

If f={(a, 0), (b, 2), (c, -3)}, g={(a, -1), (b, 1), (c, 2)} then 2f-3g=