Abhinav walked 2 km west of his house and then turned south covering 4 km. Finally, he moved 3 km towards east and then again 1 km west. How far is he from his initial position?
1) 2km
2) 4 km
3) 9 km
4) 10 km
5) none of these

Options

A. 2km
B. 4 km
C. 9 km
D. 10 km

Answer

B

Explanation

2, Abhinav starts from his house at A, moves 2 km west upto B, then 4 km to the south upto C, 3 km east upto D and finally 1 km west upto E. Thus his distance from the initial position A = AE = BC = 4 km. Hence, the answer is (2).