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Abhinav walked 2 km west of his house an...

Abhinav walked 2 km west of his house and then turned south covering 4 km. Finally, he moved 3 km towards east and then again 1 km west. How far is he from his initial position?
1) 2km
2) 4 km
3) 9 km
4) 10 km
5) none of these

A

2km

B

4 km

C

9 km

D

10 km

Text Solution

Verified by Experts

The correct Answer is:
B

2, Abhinav starts from his house at A, moves 2 km west upto B, then 4 km to the south upto C, 3 km east upto D and finally 1 km west upto E. Thus his distance from the initial position A = AE = BC = 4 km. Hence, the answer is (2).
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