When an object made of material P is kept immersed in the blue coloured solution Q, then a chemical change takes place to form a green coloured solution R and a brown layer of substance S is deposited on the object. P is used for making nails and S is used for making electric wires.
What could the material P be ?

Answer

To solve the question, we need to analyze the information provided step by step.

### Step 1: Identify the blue colored solution Q
The blue colored solution mentioned in the question is likely to be copper sulfate (CuSO4). This is a common blue solution used in various chemical reactions.

**Hint:** Look for common blue solutions in chemistry; copper sulfate is a well-known example.

### Step 2: Understand the reaction taking place
When an object made of material P is immersed in the blue solution (CuSO4), a chemical reaction occurs. In this reaction, the more reactive metal will displace the less reactive metal from the solution.

**Hint:** Consider the reactivity series of metals to determine which metal can displace another.

### Step 3: Identify the materials involved
Since the question states that a green colored solution R is formed and a brown layer of substance S is deposited on the object, we can deduce the following:
- The green colored solution R is likely ferrous sulfate (FeSO4).
- The brown layer S is copper (Cu), which is deposited on the object.

**Hint:** Look for the products of the reaction to identify the substances formed.

### Step 4: Determine the material P
Given that P is used for making nails and that iron is commonly used to make nails, we can conclude that material P is iron (Fe).

**Hint:** Think about common materials used in construction and manufacturing.

### Final Conclusion
Thus, the material P that is used for making nails is **iron (Fe)**.

---