Prove that the product of two consecutive positive integers is divisible by 2.

Prove that the product of r consecutive natural numbers is always divisible by r!.

Represent the following situations in the form of quadratic equations:(ii) The product of two consecutive positive integers is 306.We need to find the integers.

Find the sum of the first 40 positive integers divisible by 6.

Find two cosecutive positive integers,sum of whose squares is 365.

Find the sum of first 15 positive integer which are are divisible by 8.

The product of any three consecutive natural number is divisible by 6.True or False

Do you think the reverse is also true, I,e., is thesum of any two consecutive positive integers is perfect square of a number? Give example to support you answer.

Prove that: 33! is divisible by 2^15 .

Write down the form of any positive integer: When it is dividing by 2.

Express the following as the sum of two consecutive integers. 21^2