Home
Class 10
MATHS
Applying formula of quadratic equation, ...

Applying formula of quadratic equation, solve the following equations.
`(x-1)/(x-2)+(x-3)/(x-4)=3 1/3, x ne 2, 4`.

Promotional Banner

Topper's Solved these Questions

  • ALGEBRIC METHOD OF SOLVING A PAIR OF LINEAR EQUATIONS

    KALYANI PUBLICATION|Exercise EXERCISE|39 Videos
  • AREA OF SIMILAR TRIANGLES

    KALYANI PUBLICATION|Exercise EXERCISE|20 Videos

Similar Questions

Explore conceptually related problems

Applying formula of quadratic equation, solve the following equations. (2x-1)/(x+2)+(x+2)/(2x-1)=10/3, x ne 1/2, -2 .

Applying formula of quadratic equation, solve the following equations. a^2x^2+2ax=8 .

Applying formula of quadratic equation, solve the following equations. 2x+3=12/(x-1)x ne 1 .

Applying formula of quadratic equation, solve the following equations. (1-2x)/(3-x)=(x-2)/(3x-1),x ne 3, 1/3 .

Applying formula of quadratic equation, solve the following equations. (5x-6)/(4x-1)=(2x+3)/(3x+2), x ne 1/4, -2/3 .

Solve the following equations. x/3 = 1

Applying formula of quadratic equation, solve the following equations. 1/(4-x)-1/(2+x)=1/4, x ne -2,4 .

Applying formula of quadratic equation, solve the following equations. x/(2a)=(4ax)/(x+2a) , x ne -2a .

Applying formula of quadratic equation, solve the following equations. 1/(2x-1)-1(2x+1)=1/4, x ne 1/2, -1/2 .

Applying formula of quadratic equation, solve the following equations. (a - b) x^2 - (a + b) x + 2b = 0

KALYANI PUBLICATION-ALGEBRIC METHOD OF SOLVING A PAIR OF LINEAR EQUATIONS-EXERCISE
  1. Applying formula of quadratic equation, solve the following equations....

    Text Solution

    |

  2. Solve by the method of elimination: 5x-3y=1, 2x+5y=19

    Text Solution

    |

  3. Solve by the method of elimination: 3x+4y=7, 5x-8y=8

    Text Solution

    |

  4. Solve by the method of elimination: 5x-3y=16, 3x-y=12

    Text Solution

    |

  5. Solve by the method of substitution: 2x+3y=31, 17x-11y=8

    Text Solution

    |

  6. Solve by the method of substitution: ax+by=1, bx+ay=(a+b)^2/(a^2+b^2...

    Text Solution

    |

  7. Solve by the method of substitution: x+y=a+b, ax-by=a^2-b^2

    Text Solution

    |

  8. Solve by the method of cross multiplication: 8x+3y=1, 7x+4y=-6

    Text Solution

    |

  9. Solve by the method of cross multiplication: 2x+y=35, 3x+4y=65

    Text Solution

    |

  10. Solve by the method of cross multiplication: ax+by=a-b, bx-ay=a+b

    Text Solution

    |

  11. Solve by any method: (xy)/(x+y)=6/5, (xy)/(y-x)=6

    Text Solution

    |

  12. Solve by any method: (x+y)/(xy)=1, (x-y)/(xy)=65

    Text Solution

    |

  13. Solve by any method: x+2y=1.3, 3/(2x+5y)=1

    Text Solution

    |

  14. Solve by any method: 31x+43y=117, 43x+31y=105

    Text Solution

    |

  15. Solve by any method: 148x+231y=527, 231x+148y=610

    Text Solution

    |

  16. Solve by any method: ax+by=c, bx+ay=1+c

    Text Solution

    |

  17. Solve by any method: x+5y=36, (x+y)/(x-y)=5/3

    Text Solution

    |

  18. Solve by any method: x-y=0.9, 11/(2(x+y))=1

    Text Solution

    |

  19. Solve by any method: x/a+y/b=a+b, x/a^2+y/b^2=2

    Text Solution

    |

  20. Solve by any method: x/a+y/b=2, ax-by=a^2-b^2

    Text Solution

    |

  21. Word Problem of Numbers A number between 10 and 100 is equal to eigh...

    Text Solution

    |