In a certain star, three alpha particles undergo fusion in a single reaction to form 6 12 ​ C nucleus. Calculate the energy released in this reaction in MeV. Given: m( 2 4 ​ He)=4.002604 u and m( 6 12 ​ C)=12.000000 u.

For the reaction C_12H_22O_11 + H_2O overset(H+)rarr C_6H_12O_6 + C_6H_12O_6 Write rate of reaction expression

The potential energy function for a particle executing linear simple harmonic motion is given by V(x) =kx^2/2, where k is the force constant of the oscillator. For k = 0.5 N ^-1 , the graph of V(x) versus x is shown in Fig. 6.12. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x = ± 2 m.,br>

For the reaction C_12H_22O_11 + H_2O overset(H+)rarr C_6H_12O_6 + C_6H_12O_6 Write rate of law equation.

Calculate the formula unit masses ofZnO, Na_2O, K_2CO_3 , given atomic masses of Zn = 65u, Na = 23u, K = 39u, C =.12u, and O = 16u.