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The total railway fare for 5 members in ...

The total railway fare for 5 members in 3-tier and 3 members in 2-tier is Rs 2,050 whereas, the total railway fare for 8 members in 3-tier and 5 members in 2-tier is Rs 3,350. Find the fare to be paid by a couple travelling through 2-tier.

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To solve the problem step by step, we will define the variables, set up the equations, solve them, and then find the fare for a couple traveling in 2-tier. ### Step 1: Define the Variables Let: - \( x \) = fare for one member traveling in 3-tier - \( y \) = fare for one member traveling in 2-tier ### Step 2: Set Up the Equations From the problem statement, we can form two equations based on the given information: 1. For 5 members in 3-tier and 3 members in 2-tier: \[ 5x + 3y = 2050 \quad \text{(Equation 1)} \] 2. For 8 members in 3-tier and 5 members in 2-tier: \[ 8x + 5y = 3350 \quad \text{(Equation 2)} \] ### Step 3: Solve the Equations To eliminate one of the variables, we can multiply both equations by suitable numbers so that the coefficients of \( y \) are the same. - Multiply Equation 1 by 5: \[ 25x + 15y = 10250 \quad \text{(Equation 3)} \] - Multiply Equation 2 by 3: \[ 24x + 15y = 10050 \quad \text{(Equation 4)} \] ### Step 4: Subtract the Equations Now, we can subtract Equation 4 from Equation 3 to eliminate \( y \): \[ (25x + 15y) - (24x + 15y) = 10250 - 10050 \] This simplifies to: \[ x = 200 \] ### Step 5: Substitute to Find \( y \) Now that we have \( x \), we can substitute it back into one of the original equations to find \( y \). We will use Equation 1: \[ 5(200) + 3y = 2050 \] This simplifies to: \[ 1000 + 3y = 2050 \] Now, isolate \( 3y \): \[ 3y = 2050 - 1000 \] \[ 3y = 1050 \] Now, divide by 3: \[ y = 350 \] ### Step 6: Calculate the Fare for a Couple in 2-tier The fare for a couple traveling in 2-tier is: \[ 2y = 2(350) = 700 \] ### Final Answer The fare to be paid by a couple traveling through 2-tier is **Rs 700**. ---
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