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For solving each pair of equations, in t...

For solving each pair of equations, in this exercise, use the method of elimination by equation coefficiients :
2x - 3y -3 = 0
`(2x)/(3) + 4y + (1)/(2) = 0`

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To solve the given pair of equations using the method of elimination by equation coefficients, we will follow these steps: ### Given Equations: 1. \( 2x - 3y - 3 = 0 \) 2. \( \frac{2x}{3} + 4y + \frac{1}{2} = 0 \) ### Step 1: Rearranging the Equations First, let's rearrange both equations in standard form \( Ax + By + C = 0 \). 1. For the first equation: \[ 2x - 3y - 3 = 0 \implies 2x - 3y = 3 \] 2. For the second equation, we will eliminate the fractions by multiplying through by 6 (the least common multiple of the denominators 3 and 2): \[ 6 \left( \frac{2x}{3} + 4y + \frac{1}{2} \right) = 0 \implies 4x + 24y + 3 = 0 \implies 4x + 24y = -3 \] ### Step 2: Writing the Equations in Standard Form Now we have the equations: 1. \( 2x - 3y = 3 \) (Equation 1) 2. \( 4x + 24y = -3 \) (Equation 2) ### Step 3: Making Coefficients of \( x \) Equal To eliminate \( x \), we will multiply the first equation by 2 so that the coefficients of \( x \) in both equations become equal: \[ 2(2x - 3y) = 2(3) \implies 4x - 6y = 6 \quad \text{(Equation 3)} \] ### Step 4: Subtracting the Equations Now we will subtract Equation 2 from Equation 3: \[ (4x - 6y) - (4x + 24y) = 6 - (-3) \] This simplifies to: \[ -6y - 24y = 6 + 3 \implies -30y = 9 \] ### Step 5: Solving for \( y \) Now we can solve for \( y \): \[ y = \frac{9}{-30} = -\frac{3}{10} \] ### Step 6: Substituting \( y \) Back to Find \( x \) Now we substitute \( y = -\frac{3}{10} \) back into one of the original equations to find \( x \). We can use Equation 1: \[ 2x - 3\left(-\frac{3}{10}\right) = 3 \] This simplifies to: \[ 2x + \frac{9}{10} = 3 \] Subtracting \( \frac{9}{10} \) from both sides: \[ 2x = 3 - \frac{9}{10} = \frac{30}{10} - \frac{9}{10} = \frac{21}{10} \] Now, divide by 2: \[ x = \frac{21}{20} \] ### Final Solution Thus, the solution to the system of equations is: \[ x = \frac{21}{20}, \quad y = -\frac{3}{10} \]
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ICSE-SIMULTANEOUS EQUATIONS-EXERCISE 6 (B)
  1. For solving each pair of equations, in this exercise, use the method o...

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  2. For solving each pair of equations, in this exercise, use the method o...

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  3. For solving each pair of equations, in this exercise, use the method o...

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  4. For solving each pair of equations, in this exercise, use the method o...

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  5. For solving each pair of equations, in this exercise, use the method o...

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  6. For solving each pair of equations, in this exercise, use the method o...

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  7. For solving each pair of equations, in this exercise, use the method o...

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  8. For solving each pair of equations, in this exercise, use the method o...

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  9. For solving each pair of equations, in this exercise, use the method o...

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  10. For solving each pair of equations, in this exercise, use the method o...

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  11. If 2x + y = 23 and 4x - y = 19, find the values of x - 3y and 5y - 2x.

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  12. If 10y=7x-4 and 12x+18y=1. Find the value of 4x+6y and 8y-x.

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  13. Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6...

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  14. Solve for x and y : 4x = 17 - (x - y)/(8) 2y + x = 2 + (5y + 2)/(3...

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  15. Find the value of m, if x = 2, y = 1 is a solution of the equation 2x ...

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  16. 10% of x + 20% of y = 24 3x - y = 20

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  17. The value of expression mx-ny is 3 when x=5 and y=6. And its value is ...

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  18. Solve 11(x - 5) + 10(y - 2) + 54 = 0 7(2x - 1) + 9 (3y - 1) = 25

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  19. Solve : (7 + x)/(5) - (2x - y)/(4) = 3y - 5 (5y - 7)/(2) + (4x - 3...

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  20. Solve for x and y : 4x = 17 - (x - y)/(8) 2y + x = 2 + (5y + 2)/(3...

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