Home
Class 9
MATHS
In an examination, the ratio of passes t...

In an examination, the ratio of passes to failures was 4: 1. Had 30 less appeared and 20 less passed, the ratio of passes to failures would have been 5: 1. Find the number of students who appeared for the examination.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the information provided in the question regarding the ratio of passes to failures and the changes in the number of students. ### Step 1: Define Variables Let: - \( x \) = number of students who passed - \( y \) = number of students who failed ### Step 2: Set Up the First Equation From the problem, we know that the ratio of passes to failures is 4:1. This can be expressed as: \[ \frac{x}{y} = \frac{4}{1} \] This implies: \[ x = 4y \quad \text{(Equation 1)} \] ### Step 3: Set Up the Second Scenario The problem states that if 30 fewer students had appeared and 20 fewer passed, the new ratio of passes to failures would be 5:1. The total number of students who appeared would then be: \[ (x + y) - 30 \] The number of students who passed would be: \[ x - 20 \] The number of students who failed would then be: \[ (y) - (x - (x - 20)) = y - (x - 20) = y - x + 20 \] ### Step 4: Set Up the Second Equation According to the new scenario, the ratio of passes to failures is now 5:1: \[ \frac{x - 20}{y - 10} = \frac{5}{1} \] This implies: \[ x - 20 = 5(y - 10) \] Expanding this gives: \[ x - 20 = 5y - 50 \] Rearranging this, we have: \[ x - 5y = -30 \quad \text{(Equation 2)} \] ### Step 5: Substitute Equation 1 into Equation 2 Now, we can substitute \( x = 4y \) from Equation 1 into Equation 2: \[ 4y - 5y = -30 \] This simplifies to: \[ -y = -30 \] Thus: \[ y = 30 \] ### Step 6: Find the Value of \( x \) Now that we have \( y \), we can find \( x \) using Equation 1: \[ x = 4y = 4 \times 30 = 120 \] ### Step 7: Calculate the Total Number of Students The total number of students who appeared for the examination is the sum of those who passed and those who failed: \[ \text{Total Students} = x + y = 120 + 30 = 150 \] ### Final Answer The number of students who appeared for the examination is: \[ \boxed{150} \]
Promotional Banner

Topper's Solved these Questions

  • SIMULTANEOUS EQUATIONS

    ICSE|Exercise EXERCISE 6 (G)|13 Videos
  • SIMULTANEOUS EQUATIONS

    ICSE|Exercise EXERCISE 6 (E)|18 Videos
  • RECTILINEAR FIGURES

    ICSE|Exercise QUADRILATERALS AND ITS PROPERTIES - 4 MARKS QUESTIONS|7 Videos
  • SIMULTANEOUS LINEAR EQUATIONS IN TWO VARIABLES

    ICSE|Exercise Topic 2 (4 Marks questions)|8 Videos

Similar Questions

Explore conceptually related problems

In an examination, 15% students failed and 425 students passed. Find the number of students who failed in the examination, 15% students failed and 425 students passed. Find the number of students who failed in the examination.

The area of a recangular field is 260m^(2) . Had its length been 5 m less and the breadth 2m more, the field would have heen in the shape of a square. Find the perimeter of the field.

In an examination, 8% of the students fail. What percentage of the students pass? If 1650 students appeared in the examination, how many passed?

Express the following ratios in the language of daily life: (i) In an examination, the ratio of the number of students passing the examination to the total number of students that appeared in the examination is 4:5. (ii) Water is formed by combining volumes of oxygen and hydrogen in the ratio 1:2. (iii) To dilute an acid, students were asked to mix acid and water in the ratio 2:3.

100 students appeared for two examinations. 60 passed the first, 50 passed the second and 30 passed both. Find the probability that a student selected at random has passed at least one examination.

100 students appeared for two examinations .60 passed the first , 50 passed the second and 30 passed both . Find the probability that a student selected at random has failed in both examinations .

In a class of 10 student, probability of exactly I students passing an examination is directly proportional to i^(2). Then answer the following questions: If a students selected at random is found to have passed the examination, then the probability that he was the only student who has passed the examination is

The probability to pass in an examination of mathematics for three students are 1/4,1/5,1/6 . Find the probability that at least two students will pass in this examination.

The students of a class are made to stand in rows. If 3 students are extra in a row, there would be 1 row less. If 3 students are less in a row there would be 2 rows more. Find the number of students in the class.

The students of a class are made to stand in rows. If 3 students are extra in a row; there would be 1 row less. If 3 students are less in a row, there would be 2 rows more. Find the number of students in the class.