Calculate the wavelength and energy of radiation emitted for the electronic transition from infinity `(oo)` to stationary state one of the hydrogen atom `("R = 1.09678 "xx 10^(7) m^(-1))`

Options

A. 91 nm
B. 192 nm
C. 406 nm
D. `9.1 xx 10^(-8)m`

Answer

A

Explanation

`barv=1/lambda, R_(H) (1/n_(1)^2-1/n_(2)^2)`
`=1.097 xx 10^(7) (1/1^2-1/oo^2)`
`or lambda=1/(1.097 xx 10^(7)) =9.11 xx 10^(-8)m`