The transitions corresponding to Lyman series involve very long wavelengths.

An electron in hydrogen-like atom makes a transition from nth orbit or emits radiation corresponding to Lyman series. If de Broglie wavelength of electron in nth orbit is equal to the wavelength of rediation emitted , find the value of n . The atomic number of atomis 11 .

Wavelength corresponding to series limit is

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is:

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is

What is the ratio of Deltav==v_("max")-v_("min") for spectral lines corresponding to lyman & Balmer series for hydrogen

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

The shortest wavelength in Lyman series is 91.2 nm. The longest wavelength of the series is