Yellow ligth emitted from a sodium lamp has a wavelength `(lamda)` of 580 nm. Calculate the frequency (v) and wavenumber `(barv)` of the yellow light .

Explanation

`lambda=580nm=580 xx 10^(-9)m, c=3.0 xx 10^(8)ms^(-1)`
`v=c/lambda=(3.0 xx 10^(8))/(580 xx 10^(-9))=5.17 xx 10^(14) s^(-1)`
`barv=1/lambda=1/(580 xx 10^(-9))=1.72 xx 10^(6) m^(-1)`