calculate the wavelength frequency and wavenumber of a light wave whose period is ` 2.0 xx 10^(-10) s` .

Explanation

Frequency (v) `=1/("Period")=(1)/(2.0 xx 10^(-10))=5.0 xx 10^(9) s^(-1)`
Wavelength `(lambda)=c/v=(3.0 xx 10^(8))/(5 xx 10^(9)) =6.0 xx 10^(-2)m`
Wave number `(barv)=1/lambda=(1)/(6.0 xx 10^(-2))=16.67 m^(-1)`