an atom of an element contains 29 electrons and 35 neutrons . Dedue (i) the number of protons and (ii) the electronic configuration of the element.

Explanation

For a neutral atom,
Z =No. of protons = No. of electrons.
Therefore, the atomic number (Z) of the given element = 29
(i) No. of protons present in it = 29
(ii) Electronic configuration of the given element with Z = 29 is as follows:
`1s^2 2s^2 2p^6 3s^2 3p^6 3d^(10) 4s^1 or [Ar] 3d^(10) 4s^(1).`