If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Explanation

Diameter of carbon atom = 0.15 nm
`=1.5 xx 10^(-10)m=1.5 xx 10^(-8)cm`
Length along which C atoms are to be placed =20cm
Number of carbon atoms which can be placed along the length `=(20)/(1.5 xx 10^(-8)) =1.33 xx 10^(9)`