A bomb is fired from a cannon with a velocity of `1000 ms^(-1)` making an angle of `30^(@)` with the horizontal `(g = 9.8 m//s^(2)).`
What is the total time of its motion ?

Explanation

To solve the problem of finding the total time of motion for a bomb fired from a cannon, we can follow these steps:

### Step 1: Identify the initial velocity and angle
The bomb is fired with an initial velocity \( u = 1000 \, \text{m/s} \) at an angle \( \theta = 30^\circ \) with the horizontal.

### Step 2: Break down the initial velocity into components
We can find the horizontal and vertical components of the initial velocity using trigonometric functions:
- The horizontal component \( u_x = u \cos(\theta) \)
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