A bomb is fired from a cannon with a velocity of `1000 ms^(-1)` making an angle of `30^(@)` with the horizontal `(g = 9.8 m//s^(2)).`
With what speed the bomb will hit the ground and what will be it direction of motion while hitting?

Explanation

To solve the problem of a bomb fired from a cannon with an initial velocity of \(1000 \, \text{m/s}\) at an angle of \(30^\circ\) with the horizontal, we need to determine the speed at which the bomb will hit the ground and the direction of motion upon impact.

### Step 1: Understand the motion of the bomb
The bomb is fired at an angle, which means it will have both horizontal and vertical components of its initial velocity. The horizontal component will remain constant throughout the motion, while the vertical component will be affected by gravity.

### Step 2: Calculate the initial velocity components
The initial velocity \(v_0 = 1000 \, \text{m/s}\) can be broken down into horizontal and vertical components using trigonometric functions:

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