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A bomb is fired from a cannon with a vel...

A bomb is fired from a cannon with a velocity of `1000 ms^(-1)` making an angle of `30^(@)` with the horizontal `(g = 9.8 m//s^(2)).`
What is the maximum height attained by the bomb?

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To find the maximum height attained by the bomb fired from a cannon, we can follow these steps: ### Step 1: Determine the initial velocity components The initial velocity \( v_0 = 1000 \, \text{m/s} \) is given, and it is fired at an angle \( \theta = 30^\circ \) with the horizontal. We need to find the vertical component of the initial velocity \( v_{0y} \). \[ v_{0y} = v_0 \sin(\theta) = 1000 \sin(30^\circ) \] ...
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