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For an internal combustion engine to mov...

For an internal combustion engine to move a vehicle down the road ,it must convert the energy stored in the fuel into mechanical energy to drive the wheels. In your car, the distributor and battery provide this starting energy by creating an electrical "spark", which helps in combustion of fuels like gasoline. Below is the reaction depicting complete combustion of gasoline in full supply of air:
`2C_8 H_(18)(l) +25 O_(2) (g) to 16 'x' `
Which of the following are the products obtained from the reaction mentioned in the above case?
Product 'X' product 'Y'

A

`CO_2 " " H_2O_2`

B

`H_2O " " CO`

C

`CH_3OH " " H_2O`

D

`CO_2 " " H_2 O`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the products of the combustion reaction of gasoline (C₈H₁₈) with oxygen (O₂), we can follow these steps: ### Step-by-Step Solution: 1. **Write the Balanced Chemical Equation**: The complete combustion of octane (C₈H₁₈) in the presence of oxygen can be represented as: \[ 2C_8H_{18}(l) + 25O_2(g) \rightarrow 16CO_2(g) + 18H_2O(l) \] 2. **Identify the Products**: From the balanced equation, we can see that the products formed from the combustion of octane are: - Carbon Dioxide (CO₂) - Water (H₂O) 3. **Assign the Variables**: In the question, we have: - Product 'X' corresponds to the first product formed, which is Carbon Dioxide (CO₂). - Product 'Y' corresponds to the second product formed, which is Water (H₂O). 4. **Conclusion**: Therefore, we can conclude that: - Product 'X' = CO₂ - Product 'Y' = H₂O ### Final Answer: - Product 'X' is Carbon Dioxide (CO₂). - Product 'Y' is Water (H₂O).
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