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In DeltaABC,angleABC=angleDAC, AB = 8 cm...

In `DeltaABC,angleABC=angleDAC`, AB = 8 cm, AC = 4 cm and AD = 5 cm.

(iii) Find area of `DeltaACD` : area of `DeltaABC`.

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The correct Answer is:
`25:64`
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ICSE-MATHEMATICS -2014-SECTION- B
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